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14434455443413 is a prime number
BaseRepresentation
bin1101001000001100100010…
…0101101101011111010101
31220002220212000111012111011
43102003020211231133111
53342443231043142123
650411033003012221
73016566155604265
oct322031045553725
956086760435434
1014434455443413
114665688879655
1217515b1b0a071
13809217a30315
1437c8ba6a77a5
151a071765be0d
hexd20c896d7d5

14434455443413 has 2 divisors, whose sum is σ = 14434455443414. Its totient is φ = 14434455443412.

The previous prime is 14434455443333. The next prime is 14434455443453. The reversal of 14434455443413 is 31434455443441.

14434455443413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9091298371684 + 5343157071729 = 3015178^2 + 2311527^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14434455443413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14434455443453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7217227721706 + 7217227721707.

It is an arithmetic number, because the mean of its divisors is an integer number (7217227721707).

Almost surely, 214434455443413 is an apocalyptic number.

It is an amenable number.

14434455443413 is a deficient number, since it is larger than the sum of its proper divisors (1).

14434455443413 is an equidigital number, since it uses as much as digits as its factorization.

14434455443413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11059200, while the sum is 49.

The spelling of 14434455443413 in words is "fourteen trillion, four hundred thirty-four billion, four hundred fifty-five million, four hundred forty-three thousand, four hundred thirteen".