Search a number
-
+
144346220064353 is a prime number
BaseRepresentation
bin100000110100100000111001…
…001010111110111001100001
3200221002100211021001210222202
4200310200321022332321201
5122404432024314024403
61230555423230342545
742255445616216006
oct4064407112767141
9627070737053882
10144346220064353
1141aa19851455aa
121423332105aa55
136270a36c46b28
1427905740718ad
1511a4b9a744688
hex8348392bee61

144346220064353 has 2 divisors, whose sum is σ = 144346220064354. Its totient is φ = 144346220064352.

The previous prime is 144346220064301. The next prime is 144346220064443. The reversal of 144346220064353 is 353460022643441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114941813672464 + 29404406391889 = 10721092^2 + 5422583^2 .

It is a cyclic number.

It is not a de Polignac number, because 144346220064353 - 214 = 144346220047969 is a prime.

It is a super-2 number, since 2×1443462200643532 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 144346220064298 and 144346220064307.

It is not a weakly prime, because it can be changed into another prime (144346220064253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72173110032176 + 72173110032177.

It is an arithmetic number, because the mean of its divisors is an integer number (72173110032177).

Almost surely, 2144346220064353 is an apocalyptic number.

It is an amenable number.

144346220064353 is a deficient number, since it is larger than the sum of its proper divisors (1).

144346220064353 is an equidigital number, since it uses as much as digits as its factorization.

144346220064353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4976640, while the sum is 47.

The spelling of 144346220064353 in words is "one hundred forty-four trillion, three hundred forty-six billion, two hundred twenty million, sixty-four thousand, three hundred fifty-three".