Base | Representation |
---|---|
bin | 11010111000110010… |
… | …01101001100011011 |
3 | 1101021000000122210001 |
4 | 31130121031030123 |
5 | 214030330412103 |
6 | 10344212233431 |
7 | 1020466406116 |
oct | 153431151433 |
9 | 41230018701 |
10 | 14435013403 |
11 | 6138209248 |
12 | 296a30b877 |
13 | 149078c365 |
14 | 9ad19357d |
15 | 59741101d |
hex | 35c64d31b |
14435013403 has 2 divisors, whose sum is σ = 14435013404. Its totient is φ = 14435013402.
The previous prime is 14435013401. The next prime is 14435013427. The reversal of 14435013403 is 30431053441.
It is a weak prime.
It is an emirp because it is prime and its reverse (30431053441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14435013403 - 21 = 14435013401 is a prime.
It is a super-2 number, since 2×144350134032 (a number of 21 digits) contains 22 as substring.
Together with 14435013401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (14435013401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7217506701 + 7217506702.
It is an arithmetic number, because the mean of its divisors is an integer number (7217506702).
Almost surely, 214435013403 is an apocalyptic number.
14435013403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14435013403 is an equidigital number, since it uses as much as digits as its factorization.
14435013403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 14435013403 its reverse (30431053441), we get a palindrome (44866066844).
The spelling of 14435013403 in words is "fourteen billion, four hundred thirty-five million, thirteen thousand, four hundred three".
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