14441240141113 has 2 divisors, whose sum is σ = 14441240141114. Its totient is φ = 14441240141112.

The previous prime is 14441240141057. The next prime is 14441240141131. The reversal of 14441240141113 is 31114104214441.

Together with next prime (14441240141131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11764570722304 + 2676669418809 = 3429952^2 + 1636053^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14441240141113 is a prime.

It is not a weakly prime, because it can be changed into another prime (14441240144113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7220620070556 + 7220620070557.

It is an arithmetic number, because the mean of its divisors is an integer number (7220620070557).

Almost surely, 2^{14441240141113} is an apocalyptic number.

It is an amenable number.

14441240141113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14441240141113 is an equidigital number, since it uses as much as digits as its factorization.

14441240141113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 31.

Adding to 14441240141113 its reverse (31114104214441), we get a palindrome (45555344355554).

The spelling of 14441240141113 in words is "fourteen trillion, four hundred forty-one billion, two hundred forty million, one hundred forty-one thousand, one hundred thirteen".