14441240141131 has 2 divisors, whose sum is σ = 14441240141132. Its totient is φ = 14441240141130.

The previous prime is 14441240141113. The next prime is 14441240141161. The reversal of 14441240141131 is 13114104214441.

Together with previous prime (14441240141113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14441240141131 - 2³⁵ = 14406880402763 is a prime.

It is a super-2 number, since 2×14441240141131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14441240141093 and 14441240141102.

It is not a weakly prime, because it can be changed into another prime (14441240141161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7220620070565 + 7220620070566.

It is an arithmetic number, because the mean of its divisors is an integer number (7220620070566).

Almost surely, 2^{14441240141131} is an apocalyptic number.

14441240141131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14441240141131 is an equidigital number, since it uses as much as digits as its factorization.

14441240141131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 31.

Adding to 14441240141131 its reverse (13114104214441), we get a palindrome (27555344355572).

The spelling of 14441240141131 in words is "fourteen trillion, four hundred forty-one billion, two hundred forty million, one hundred forty-one thousand, one hundred thirty-one".