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14441243141113 is a prime number
BaseRepresentation
bin1101001000100101110100…
…1010101110001111111001
31220010120101001201222021021
43102021131022232033321
53343101131221003423
650414114314542441
73020226316230355
oct322113512561771
956116331658237
1014441243141113
1146685512a8378
121752987137a21
13809a5a0624a9
1437cd61d5c465
151a09b34db95d
hexd225d2ae3f9

14441243141113 has 2 divisors, whose sum is σ = 14441243141114. Its totient is φ = 14441243141112.

The previous prime is 14441243141107. The next prime is 14441243141153. The reversal of 14441243141113 is 31114134214441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10220470120809 + 4220773020304 = 3196947^2 + 2054452^2 .

It is an emirp because it is prime and its reverse (31114134214441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14441243141113 - 225 = 14441209586681 is a prime.

It is not a weakly prime, because it can be changed into another prime (14441243141153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7220621570556 + 7220621570557.

It is an arithmetic number, because the mean of its divisors is an integer number (7220621570557).

Almost surely, 214441243141113 is an apocalyptic number.

It is an amenable number.

14441243141113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14441243141113 is an equidigital number, since it uses as much as digits as its factorization.

14441243141113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 18432, while the sum is 34.

Adding to 14441243141113 its reverse (31114134214441), we get a palindrome (45555377355554).

The spelling of 14441243141113 in words is "fourteen trillion, four hundred forty-one billion, two hundred forty-three million, one hundred forty-one thousand, one hundred thirteen".