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14441420111 is a prime number
BaseRepresentation
bin11010111001100011…
…01001010101001111
31101021110002011010112
431130301221111033
5214034000420421
610345001430235
71020605021426
oct153461512517
941243064115
1014441420111
116140894748
12297049b37b
131491bc3501
149add802bd
15597c7945b
hex35cc6954f

14441420111 has 2 divisors, whose sum is σ = 14441420112. Its totient is φ = 14441420110.

The previous prime is 14441420089. The next prime is 14441420143. The reversal of 14441420111 is 11102414441.

It is a weak prime.

It is an emirp because it is prime and its reverse (11102414441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14441420111 - 214 = 14441403727 is a prime.

It is a super-2 number, since 2×144414201112 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14441420911) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7220710055 + 7220710056.

It is an arithmetic number, because the mean of its divisors is an integer number (7220710056).

Almost surely, 214441420111 is an apocalyptic number.

14441420111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14441420111 is an equidigital number, since it uses as much as digits as its factorization.

14441420111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 512, while the sum is 23.

Adding to 14441420111 its reverse (11102414441), we get a palindrome (25543834552).

The spelling of 14441420111 in words is "fourteen billion, four hundred forty-one million, four hundred twenty thousand, one hundred eleven".