Base | Representation |
---|---|
bin | 11010111001100011… |
… | …01001010101001111 |
3 | 1101021110002011010112 |
4 | 31130301221111033 |
5 | 214034000420421 |
6 | 10345001430235 |
7 | 1020605021426 |
oct | 153461512517 |
9 | 41243064115 |
10 | 14441420111 |
11 | 6140894748 |
12 | 297049b37b |
13 | 1491bc3501 |
14 | 9add802bd |
15 | 597c7945b |
hex | 35cc6954f |
14441420111 has 2 divisors, whose sum is σ = 14441420112. Its totient is φ = 14441420110.
The previous prime is 14441420089. The next prime is 14441420143. The reversal of 14441420111 is 11102414441.
It is a weak prime.
It is an emirp because it is prime and its reverse (11102414441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14441420111 - 214 = 14441403727 is a prime.
It is a super-2 number, since 2×144414201112 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14441420911) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7220710055 + 7220710056.
It is an arithmetic number, because the mean of its divisors is an integer number (7220710056).
Almost surely, 214441420111 is an apocalyptic number.
14441420111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14441420111 is an equidigital number, since it uses as much as digits as its factorization.
14441420111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 512, while the sum is 23.
Adding to 14441420111 its reverse (11102414441), we get a palindrome (25543834552).
The spelling of 14441420111 in words is "fourteen billion, four hundred forty-one million, four hundred twenty thousand, one hundred eleven".
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