Base | Representation |
---|---|
bin | 11010111001101001… |
… | …01010101100101111 |
3 | 1101021111120101121001 |
4 | 31130310222230233 |
5 | 214034201242033 |
6 | 10345030421131 |
7 | 1020614530522 |
oct | 153464525457 |
9 | 41244511531 |
10 | 14442212143 |
11 | 6141285817 |
12 | 29708017a7 |
13 | 149210cb78 |
14 | 9b0108bb9 |
15 | 597d83e7d |
hex | 35cd2ab2f |
14442212143 has 2 divisors, whose sum is σ = 14442212144. Its totient is φ = 14442212142.
The previous prime is 14442212117. The next prime is 14442212207. The reversal of 14442212143 is 34121224441.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14442212143 - 25 = 14442212111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14442212443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7221106071 + 7221106072.
It is an arithmetic number, because the mean of its divisors is an integer number (7221106072).
Almost surely, 214442212143 is an apocalyptic number.
14442212143 is a deficient number, since it is larger than the sum of its proper divisors (1).
14442212143 is an equidigital number, since it uses as much as digits as its factorization.
14442212143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6144, while the sum is 28.
Adding to 14442212143 its reverse (34121224441), we get a palindrome (48563436584).
The spelling of 14442212143 in words is "fourteen billion, four hundred forty-two million, two hundred twelve thousand, one hundred forty-three".
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