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14442890053 is a prime number
BaseRepresentation
bin11010111001101110…
…10000001101000101
31101021112211211111211
431130313100031011
5214034334440203
610345053131421
71020623353114
oct153467201505
941245754454
1014442890053
1161416a9079
122970a89b71
1314922b95b7
149b0243c7b
15597e69c6d
hex35cdd0345

14442890053 has 2 divisors, whose sum is σ = 14442890054. Its totient is φ = 14442890052.

The previous prime is 14442890017. The next prime is 14442890083. The reversal of 14442890053 is 35009824441.

14442890053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10315855489 + 4127034564 = 101567^2 + 64242^2 .

It is a cyclic number.

It is not a de Polignac number, because 14442890053 - 233 = 5852955461 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14442889988 and 14442890015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14442890003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7221445026 + 7221445027.

It is an arithmetic number, because the mean of its divisors is an integer number (7221445027).

Almost surely, 214442890053 is an apocalyptic number.

It is an amenable number.

14442890053 is a deficient number, since it is larger than the sum of its proper divisors (1).

14442890053 is an equidigital number, since it uses as much as digits as its factorization.

14442890053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 40.

The spelling of 14442890053 in words is "fourteen billion, four hundred forty-two million, eight hundred ninety thousand, fifty-three".