1444312400053 has 2 divisors, whose sum is σ = 1444312400054. Its totient is φ = 1444312400052.

The previous prime is 1444312399973. The next prime is 1444312400057. The reversal of 1444312400053 is 3500042134441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1146745423044 + 297566977009 = 1070862^2 + 545497^2 .

It is a cyclic number.

It is not a de Polignac number, because 1444312400053 - 2²¹ = 1444310302901 is a prime.

It is a super-2 number, since 2×1444312400053² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1444312399988 and 1444312400024.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1444312400057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 722156200026 + 722156200027.

It is an arithmetic number, because the mean of its divisors is an integer number (722156200027).

Almost surely, 2^{1444312400053} is an apocalyptic number.

It is an amenable number.

1444312400053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1444312400053 is an equidigital number, since it uses as much as digits as its factorization.

1444312400053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 1444312400053 its reverse (3500042134441), we get a palindrome (4944354534494).

The spelling of 1444312400053 in words is "one trillion, four hundred forty-four billion, three hundred twelve million, four hundred thousand, fifty-three".