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1444343305411 is a prime number
BaseRepresentation
bin10101000001001001100…
…100011101010011000011
312010002002202202002220201
4111001021210131103003
5142131003341233121
63023304441350031
7206231113346566
oct25011144352303
95102082662821
101444343305411
115075a7161a36
121b3b0b798317
13a627c75bb26
144dc999744dd
15278860d1e91
hex1504991d4c3

1444343305411 has 2 divisors, whose sum is σ = 1444343305412. Its totient is φ = 1444343305410.

The previous prime is 1444343305409. The next prime is 1444343305451. The reversal of 1444343305411 is 1145033434441.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1444343305411 - 21 = 1444343305409 is a prime.

It is a super-2 number, since 2×14443433054112 (a number of 25 digits) contains 22 as substring.

Together with 1444343305409, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1444343305451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 722171652705 + 722171652706.

It is an arithmetic number, because the mean of its divisors is an integer number (722171652706).

Almost surely, 21444343305411 is an apocalyptic number.

1444343305411 is a deficient number, since it is larger than the sum of its proper divisors (1).

1444343305411 is an equidigital number, since it uses as much as digits as its factorization.

1444343305411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 37.

Adding to 1444343305411 its reverse (1145033434441), we get a palindrome (2589376739852).

The spelling of 1444343305411 in words is "one trillion, four hundred forty-four billion, three hundred forty-three million, three hundred five thousand, four hundred eleven".