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144435020011531 is a prime number
BaseRepresentation
bin100000110101110011100110…
…000011111001100000001011
3200221101212000212211112010021
4200311303212003321200023
5122412410410110332111
61231104310541401311
742265041304264204
oct4065634603714013
9627355025745107
10144435020011531
11420266034241a7
1214248583b69237
136279219256882
1427949998285ab
1511a7146574d71
hex835ce60f980b

144435020011531 has 2 divisors, whose sum is σ = 144435020011532. Its totient is φ = 144435020011530.

The previous prime is 144435020011493. The next prime is 144435020011543. The reversal of 144435020011531 is 135110020534441.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 144435020011531 - 243 = 135638926989323 is a prime.

It is a super-2 number, since 2×1444350200115312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (144435020041531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72217510005765 + 72217510005766.

It is an arithmetic number, because the mean of its divisors is an integer number (72217510005766).

Almost surely, 2144435020011531 is an apocalyptic number.

144435020011531 is a deficient number, since it is larger than the sum of its proper divisors (1).

144435020011531 is an equidigital number, since it uses as much as digits as its factorization.

144435020011531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 144435020011531 its reverse (135110020534441), we get a palindrome (279545040545972).

The spelling of 144435020011531 in words is "one hundred forty-four trillion, four hundred thirty-five billion, twenty million, eleven thousand, five hundred thirty-one".