Base | Representation |
---|---|
bin | 100000110101111011001110… |
… | …111100111000100101011011 |
3 | 200221102122012111202110111212 |
4 | 200311323032330320211123 |
5 | 122413024204342401022 |
6 | 1231112144503413335 |
7 | 42265451462065502 |
oct | 4065731674704533 |
9 | 627378174673455 |
10 | 144443222231387 |
11 | 4202a0323603a2 |
12 | 1424a092a5424b |
13 | 6279c256504c1 |
14 | 2795136cd1839 |
15 | 11a74766b73e2 |
hex | 835ecef3895b |
144443222231387 has 2 divisors, whose sum is σ = 144443222231388. Its totient is φ = 144443222231386.
The previous prime is 144443222231351. The next prime is 144443222231389. The reversal of 144443222231387 is 783132222344441.
It is a strong prime.
It is an emirp because it is prime and its reverse (783132222344441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 144443222231387 - 218 = 144443221969243 is a prime.
Together with 144443222231389, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (144443222231389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72221611115693 + 72221611115694.
It is an arithmetic number, because the mean of its divisors is an integer number (72221611115694).
Almost surely, 2144443222231387 is an apocalyptic number.
144443222231387 is a deficient number, since it is larger than the sum of its proper divisors (1).
144443222231387 is an equidigital number, since it uses as much as digits as its factorization.
144443222231387 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6193152, while the sum is 50.
The spelling of 144443222231387 in words is "one hundred forty-four trillion, four hundred forty-three billion, two hundred twenty-two million, two hundred thirty-one thousand, three hundred eighty-seven".
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