Base | Representation |
---|---|
bin | 1000011010001000110… |
… | …1101000111000111101 |
3 | 111210212100022220120112 |
4 | 2012202031220320331 |
5 | 4331321040430432 |
6 | 150210100355405 |
7 | 13302511453412 |
oct | 2064215507075 |
9 | 453770286515 |
10 | 144455405117 |
11 | 56299345a31 |
12 | 23bb59a5b65 |
13 | 1081195369a |
14 | 6dc524a109 |
15 | 3b56e517b2 |
hex | 21a2368e3d |
144455405117 has 2 divisors, whose sum is σ = 144455405118. Its totient is φ = 144455405116.
The previous prime is 144455405113. The next prime is 144455405179. The reversal of 144455405117 is 711504554441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80331998041 + 64123407076 = 283429^2 + 253226^2 .
It is a cyclic number.
It is not a de Polignac number, because 144455405117 - 22 = 144455405113 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144455405111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72227702558 + 72227702559.
It is an arithmetic number, because the mean of its divisors is an integer number (72227702559).
Almost surely, 2144455405117 is an apocalyptic number.
It is an amenable number.
144455405117 is a deficient number, since it is larger than the sum of its proper divisors (1).
144455405117 is an equidigital number, since it uses as much as digits as its factorization.
144455405117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224000, while the sum is 41.
Adding to 144455405117 its reverse (711504554441), we get a palindrome (855959959558).
The spelling of 144455405117 in words is "one hundred forty-four billion, four hundred fifty-five million, four hundred five thousand, one hundred seventeen".
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