14448111323 has 2 divisors, whose sum is σ = 14448111324. Its totient is φ = 14448111322.

The previous prime is 14448111313. The next prime is 14448111331. The reversal of 14448111323 is 32311184441.

It is a strong prime.

It is an emirp because it is prime and its reverse (32311184441) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14448111323 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14448111323.

It is not a weakly prime, because it can be changed into another prime (14448111313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7224055661 + 7224055662.

It is an arithmetic number, because the mean of its divisors is an integer number (7224055662).

Almost surely, 2^14448111323 is an apocalyptic number.

14448111323 is a deficient number, since it is larger than the sum of its proper divisors (1).

14448111323 is an equidigital number, since it uses as much as digits as its factorization.

14448111323 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9216, while the sum is 32.

Adding to 14448111323 its reverse (32311184441), we get a palindrome (46759295764).

The spelling of 14448111323 in words is "fourteen billion, four hundred forty-eight million, one hundred eleven thousand, three hundred twenty-three".