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144511241141 is a prime number
BaseRepresentation
bin1000011010010110001…
…0101000101110110101
3111211000020101200012102
42012211202220232311
54331424334204031
6150215413231445
713304060165561
oct2064542505665
9454006350172
10144511241141
1156317912403
1224010632585
13108203a3257
146dcc8226a1
153b5bcd07cb
hex21a58a8bb5

144511241141 has 2 divisors, whose sum is σ = 144511241142. Its totient is φ = 144511241140.

The previous prime is 144511241113. The next prime is 144511241159. The reversal of 144511241141 is 141142115441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79011588100 + 65499653041 = 281090^2 + 255929^2 .

It is an emirp because it is prime and its reverse (141142115441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 144511241141 - 226 = 144444132277 is a prime.

It is a super-2 number, since 2×1445112411412 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144511241101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72255620570 + 72255620571.

It is an arithmetic number, because the mean of its divisors is an integer number (72255620571).

Almost surely, 2144511241141 is an apocalyptic number.

It is an amenable number.

144511241141 is a deficient number, since it is larger than the sum of its proper divisors (1).

144511241141 is an equidigital number, since it uses as much as digits as its factorization.

144511241141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2560, while the sum is 29.

Adding to 144511241141 its reverse (141142115441), we get a palindrome (285653356582).

The spelling of 144511241141 in words is "one hundred forty-four billion, five hundred eleven million, two hundred forty-one thousand, one hundred forty-one".