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14452022413 is a prime number
BaseRepresentation
bin11010111010110100…
…00101110010001101
31101022012000210202101
431131122011302031
5214044204204123
610350020555101
71021064110063
oct153532056215
941265023671
1014452022413
116146876384
122973b52a91
13149416626a
149b1540033
15598b70aad
hex35d685c8d

14452022413 has 2 divisors, whose sum is σ = 14452022414. Its totient is φ = 14452022412.

The previous prime is 14452022399. The next prime is 14452022471. The reversal of 14452022413 is 31422025441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11188985284 + 3263037129 = 105778^2 + 57123^2 .

It is an emirp because it is prime and its reverse (31422025441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14452022413 - 213 = 14452014221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14452022483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7226011206 + 7226011207.

It is an arithmetic number, because the mean of its divisors is an integer number (7226011207).

Almost surely, 214452022413 is an apocalyptic number.

It is an amenable number.

14452022413 is a deficient number, since it is larger than the sum of its proper divisors (1).

14452022413 is an equidigital number, since it uses as much as digits as its factorization.

14452022413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7680, while the sum is 28.

Adding to 14452022413 its reverse (31422025441), we get a palindrome (45874047854).

The spelling of 14452022413 in words is "fourteen billion, four hundred fifty-two million, twenty-two thousand, four hundred thirteen".