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14466663000151 is a prime number
BaseRepresentation
bin1101001010000100100001…
…0011110010100001010111
31220012222222121200121101221
43102201020103302201113
53344010211212001101
650433520534431211
73022116252404515
oct322411023624127
956188877617357
1014466663000151
11467830613373a
1217578a0202507
1380c27b5714bb
14380293d994b5
151a149ee96aa1
hexd28484f2857

14466663000151 has 2 divisors, whose sum is σ = 14466663000152. Its totient is φ = 14466663000150.

The previous prime is 14466662999989. The next prime is 14466663000161. The reversal of 14466663000151 is 15100036666441.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14466663000151 - 223 = 14466654611543 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14466663000098 and 14466663000107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14466663000161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7233331500075 + 7233331500076.

It is an arithmetic number, because the mean of its divisors is an integer number (7233331500076).

Almost surely, 214466663000151 is an apocalyptic number.

14466663000151 is a deficient number, since it is larger than the sum of its proper divisors (1).

14466663000151 is an equidigital number, since it uses as much as digits as its factorization.

14466663000151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 43.

Adding to 14466663000151 its reverse (15100036666441), we get a palindrome (29566699666592).

The spelling of 14466663000151 in words is "fourteen trillion, four hundred sixty-six billion, six hundred sixty-three million, one hundred fifty-one", and thus it is an aban number.