144743774016761 has 2 divisors, whose sum is σ = 144743774016762. Its totient is φ = 144743774016760.

The previous prime is 144743774016739. The next prime is 144743774016763. The reversal of 144743774016761 is 167610477347441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81402167959225 + 63341606057536 = 9022315^2 + 7958744^2 .

It is a cyclic number.

It is not a de Polignac number, because 144743774016761 - 2¹⁸ = 144743773754617 is a prime.

It is a super-2 number, since 2×144743774016761² (a number of 29 digits) contains 22 as substring.

Together with 144743774016763, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 144743774016694 and 144743774016703.

It is not a weakly prime, because it can be changed into another prime (144743774016763) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72371887008380 + 72371887008381.

It is an arithmetic number, because the mean of its divisors is an integer number (72371887008381).

Almost surely, 2^{144743774016761} is an apocalyptic number.

It is an amenable number.

144743774016761 is a deficient number, since it is larger than the sum of its proper divisors (1).

144743774016761 is an equidigital number, since it uses as much as digits as its factorization.

144743774016761 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 66382848, while the sum is 62.

The spelling of 144743774016761 in words is "one hundred forty-four trillion, seven hundred forty-three billion, seven hundred seventy-four million, sixteen thousand, seven hundred sixty-one".