Base | Representation |
---|---|
bin | 100000111011100101101010… |
… | …100111110101011000100111 |
3 | 200222210211200122200000020201 |
4 | 200323211222213311120213 |
5 | 122440413204014444331 |
6 | 1232011024411011331 |
7 | 42335536263140413 |
oct | 4073455247653047 |
9 | 628724618600221 |
10 | 144832381015591 |
11 | 4216a082346915 |
12 | 142b159b439b47 |
13 | 62a7833c1a449 |
14 | 27a9cd3317d43 |
15 | 11b2651438a61 |
hex | 83b96a9f5627 |
144832381015591 has 2 divisors, whose sum is σ = 144832381015592. Its totient is φ = 144832381015590.
The previous prime is 144832381015573. The next prime is 144832381015603. The reversal of 144832381015591 is 195510183238441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144832381015591 - 213 = 144832381007399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144832381015501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72416190507795 + 72416190507796.
It is an arithmetic number, because the mean of its divisors is an integer number (72416190507796).
Almost surely, 2144832381015591 is an apocalyptic number.
144832381015591 is a deficient number, since it is larger than the sum of its proper divisors (1).
144832381015591 is an equidigital number, since it uses as much as digits as its factorization.
144832381015591 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4147200, while the sum is 55.
The spelling of 144832381015591 in words is "one hundred forty-four trillion, eight hundred thirty-two billion, three hundred eighty-one million, fifteen thousand, five hundred ninety-one".
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