Base | Representation |
---|---|
bin | 11010111111110111… |
… | …00111000100100111 |
3 | 1101102010200222102012 |
4 | 31133323213010213 |
5 | 214141024121233 |
6 | 10354132304435 |
7 | 1022120026553 |
oct | 153773470447 |
9 | 41363628365 |
10 | 14494363943 |
11 | 6168766184 |
12 | 298617211b |
13 | 149cb6c817 |
14 | 9b7002863 |
15 | 59c736548 |
hex | 35fee7127 |
14494363943 has 2 divisors, whose sum is σ = 14494363944. Its totient is φ = 14494363942.
The previous prime is 14494363927. The next prime is 14494363957. The reversal of 14494363943 is 34936349441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14494363943 - 24 = 14494363927 is a prime.
It is a super-2 number, since 2×144943639432 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14494363891 and 14494363900.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14494363043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7247181971 + 7247181972.
It is an arithmetic number, because the mean of its divisors is an integer number (7247181972).
Almost surely, 214494363943 is an apocalyptic number.
14494363943 is a deficient number, since it is larger than the sum of its proper divisors (1).
14494363943 is an equidigital number, since it uses as much as digits as its factorization.
14494363943 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3359232, while the sum is 50.
The spelling of 14494363943 in words is "fourteen billion, four hundred ninety-four million, three hundred sixty-three thousand, nine hundred forty-three".
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