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14501112645533 is a prime number
BaseRepresentation
bin1101001100000100110110…
…1010110000011110011101
31220100021220110202220201212
43103001031222300132131
53400041234314124113
650501415202114205
73024446042511443
oct323011552603635
956307813686655
1014501112645533
114690984055148
1217624b534b965
138125ab75c457
14381c01362b93
151a23195640a8
hexd304dab079d

14501112645533 has 2 divisors, whose sum is σ = 14501112645534. Its totient is φ = 14501112645532.

The previous prime is 14501112645527. The next prime is 14501112645557. The reversal of 14501112645533 is 33554621110541.

14501112645533 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14069303322649 + 431809322884 = 3750907^2 + 657122^2 .

It is a cyclic number.

It is not a de Polignac number, because 14501112645533 - 226 = 14501045536669 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14501112605533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7250556322766 + 7250556322767.

It is an arithmetic number, because the mean of its divisors is an integer number (7250556322767).

Almost surely, 214501112645533 is an apocalyptic number.

It is an amenable number.

14501112645533 is a deficient number, since it is larger than the sum of its proper divisors (1).

14501112645533 is an equidigital number, since it uses as much as digits as its factorization.

14501112645533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 41.

The spelling of 14501112645533 in words is "fourteen trillion, five hundred one billion, one hundred twelve million, six hundred forty-five thousand, five hundred thirty-three".