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145011352033 is a prime number
BaseRepresentation
bin1000011100001101011…
…0011010000111100001
3111212022002102221101001
42013003112122013201
54333440401231113
6150341200312001
713322342104042
oct2070326320741
9455262387331
10145011352033
1156554145099
1224130012601
131089cb96962
1470390068c9
153b8ab6b7dd
hex21c359a1e1

145011352033 has 2 divisors, whose sum is σ = 145011352034. Its totient is φ = 145011352032.

The previous prime is 145011352007. The next prime is 145011352049. The reversal of 145011352033 is 330253110541.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87786578944 + 57224773089 = 296288^2 + 239217^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145011352033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 145011351992 and 145011352010.

It is not a weakly prime, because it can be changed into another prime (145011355033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72505676016 + 72505676017.

It is an arithmetic number, because the mean of its divisors is an integer number (72505676017).

Almost surely, 2145011352033 is an apocalyptic number.

It is an amenable number.

145011352033 is a deficient number, since it is larger than the sum of its proper divisors (1).

145011352033 is an equidigital number, since it uses as much as digits as its factorization.

145011352033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 145011352033 its reverse (330253110541), we get a palindrome (475264462574).

The spelling of 145011352033 in words is "one hundred forty-five billion, eleven million, three hundred fifty-two thousand, thirty-three".