Base | Representation |
---|---|
bin | 1000011100001101011… |
… | …0111111110001111111 |
3 | 111212022002201202222202 |
4 | 2013003112333301333 |
5 | 4333440421200203 |
6 | 150341203502115 |
7 | 13322343315566 |
oct | 2070326776177 |
9 | 455262652882 |
10 | 145011506303 |
11 | 5655423aa94 |
12 | 2413008793b |
13 | 1089cc1bc41 |
14 | 7039046bdd |
15 | 3b8ab9c388 |
hex | 21c35bfc7f |
145011506303 has 2 divisors, whose sum is σ = 145011506304. Its totient is φ = 145011506302.
The previous prime is 145011506261. The next prime is 145011506383. The reversal of 145011506303 is 303605110541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 145011506303 - 210 = 145011505279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145011506383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72505753151 + 72505753152.
It is an arithmetic number, because the mean of its divisors is an integer number (72505753152).
Almost surely, 2145011506303 is an apocalyptic number.
145011506303 is a deficient number, since it is larger than the sum of its proper divisors (1).
145011506303 is an equidigital number, since it uses as much as digits as its factorization.
145011506303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 145011506303 its reverse (303605110541), we get a palindrome (448616616844).
The spelling of 145011506303 in words is "one hundred forty-five billion, eleven million, five hundred six thousand, three hundred three".
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