Base | Representation |
---|---|
bin | 100000111110001100100000… |
… | …010101001111110010001001 |
3 | 201000102222002101101200202122 |
4 | 200332030200111033302021 |
5 | 123001332044423133213 |
6 | 1232225212450541025 |
7 | 42354510505066142 |
oct | 4076144025176211 |
9 | 630388071350678 |
10 | 145011523255433 |
11 | 422290504870aa |
12 | 14320255897775 |
13 | 62bb6b2c374b3 |
14 | 27b4849230ac9 |
15 | 11b71386aad08 |
hex | 83e32054fc89 |
145011523255433 has 2 divisors, whose sum is σ = 145011523255434. Its totient is φ = 145011523255432.
The previous prime is 145011523255411. The next prime is 145011523255441. The reversal of 145011523255433 is 334552325110541.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 72646506517264 + 72365016738169 = 8523292^2 + 8506763^2 .
It is a cyclic number.
It is not a de Polignac number, because 145011523255433 - 232 = 145007228288137 is a prime.
It is not a weakly prime, because it can be changed into another prime (145011523255483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72505761627716 + 72505761627717.
It is an arithmetic number, because the mean of its divisors is an integer number (72505761627717).
Almost surely, 2145011523255433 is an apocalyptic number.
It is an amenable number.
145011523255433 is a deficient number, since it is larger than the sum of its proper divisors (1).
145011523255433 is an equidigital number, since it uses as much as digits as its factorization.
145011523255433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1080000, while the sum is 44.
Adding to 145011523255433 its reverse (334552325110541), we get a palindrome (479563848365974).
The spelling of 145011523255433 in words is "one hundred forty-five trillion, eleven billion, five hundred twenty-three million, two hundred fifty-five thousand, four hundred thirty-three".
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