Base | Representation |
---|---|
bin | 100000111110001100100000… |
… | …010101001111110010111011 |
3 | 201000102222002101101200211111 |
4 | 200332030200111033302323 |
5 | 123001332044423133413 |
6 | 1232225212450541151 |
7 | 42354510505066243 |
oct | 4076144025176273 |
9 | 630388071350744 |
10 | 145011523255483 |
11 | 42229050487145 |
12 | 143202558977b7 |
13 | 62bb6b2c37521 |
14 | 27b4849230b23 |
15 | 11b71386aad3d |
hex | 83e32054fcbb |
145011523255483 has 2 divisors, whose sum is σ = 145011523255484. Its totient is φ = 145011523255482.
The previous prime is 145011523255451. The next prime is 145011523255517. The reversal of 145011523255483 is 384552325110541.
145011523255483 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 145011523255483 - 25 = 145011523255451 is a prime.
It is not a weakly prime, because it can be changed into another prime (145011523255433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72505761627741 + 72505761627742.
It is an arithmetic number, because the mean of its divisors is an integer number (72505761627742).
Almost surely, 2145011523255483 is an apocalyptic number.
145011523255483 is a deficient number, since it is larger than the sum of its proper divisors (1).
145011523255483 is an equidigital number, since it uses as much as digits as its factorization.
145011523255483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880000, while the sum is 49.
The spelling of 145011523255483 in words is "one hundred forty-five trillion, eleven billion, five hundred twenty-three million, two hundred fifty-five thousand, four hundred eighty-three".
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