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145026533453 is a prime number
BaseRepresentation
bin1000011100010001000…
…0010100100001001101
3111212100011000020100212
42013010100110201031
54334003243032303
6150342501532205
713322615123534
oct2070420244115
9455304006325
10145026533453
115656177411a
1224135114065
13108a3080a49
14703b03931b
153b8c169ad8
hex21c441484d

145026533453 has 2 divisors, whose sum is σ = 145026533454. Its totient is φ = 145026533452.

The previous prime is 145026533359. The next prime is 145026533459. The reversal of 145026533453 is 354335620541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126791542084 + 18234991369 = 356078^2 + 135037^2 .

It is a cyclic number.

It is not a de Polignac number, because 145026533453 - 212 = 145026529357 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 145026533453.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145026533459) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72513266726 + 72513266727.

It is an arithmetic number, because the mean of its divisors is an integer number (72513266727).

Almost surely, 2145026533453 is an apocalyptic number.

It is an amenable number.

145026533453 is a deficient number, since it is larger than the sum of its proper divisors (1).

145026533453 is an equidigital number, since it uses as much as digits as its factorization.

145026533453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648000, while the sum is 41.

The spelling of 145026533453 in words is "one hundred forty-five billion, twenty-six million, five hundred thirty-three thousand, four hundred fifty-three".