Base | Representation |
---|---|
bin | 101011001110010… |
… | …0000011011011101 |
3 | 10202002000120000111 |
4 | 1112130200123131 |
5 | 10432240012222 |
6 | 355525130021 |
7 | 50640314026 |
oct | 12634403335 |
9 | 3662016014 |
10 | 1450313437 |
11 | 684733a51 |
12 | 345859911 |
13 | 1a1616741 |
14 | da88bc4d |
15 | 874d2777 |
hex | 567206dd |
1450313437 has 2 divisors, whose sum is σ = 1450313438. Its totient is φ = 1450313436.
The previous prime is 1450313429. The next prime is 1450313483. The reversal of 1450313437 is 7343130541.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1237562041 + 212751396 = 35179^2 + 14586^2 .
It is a cyclic number.
It is not a de Polignac number, because 1450313437 - 23 = 1450313429 is a prime.
It is a super-3 number, since 3×14503134373 (a number of 28 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1450313399 and 1450313408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1450316437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 725156718 + 725156719.
It is an arithmetic number, because the mean of its divisors is an integer number (725156719).
Almost surely, 21450313437 is an apocalyptic number.
It is an amenable number.
1450313437 is a deficient number, since it is larger than the sum of its proper divisors (1).
1450313437 is an equidigital number, since it uses as much as digits as its factorization.
1450313437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 31.
The square root of 1450313437 is about 38082.9809363710. The cubic root of 1450313437 is about 1131.9327450397.
Adding to 1450313437 its reverse (7343130541), we get a palindrome (8793443978).
The spelling of 1450313437 in words is "one billion, four hundred fifty million, three hundred thirteen thousand, four hundred thirty-seven".
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