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145033340211254 = 2112599311323187
BaseRepresentation
bin100000111110100000110100…
…101110010101000000110110
3201000112001101211211212211102
4200332200310232111000312
5123002211240043230004
61232243221404010102
742356212242130265
oct4076406456250066
9630461354755742
10145033340211254
11422373265a0a00
1214324524230932
1362c077bb8ab01
1427b59189645dc
1511b79b3bce11e
hex83e834b95036

145033340211254 has 12 divisors (see below), whose sum is σ = 239125217952012. Its totient is φ = 65924245550460.

The previous prime is 145033340211223. The next prime is 145033340211317. The reversal of 145033340211254 is 452112043330541.

It is a super-2 number, since 2×1450333402112542 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 299655661352 + ... + 299655661835.

It is an arithmetic number, because the mean of its divisors is an integer number (19927101496001).

Almost surely, 2145033340211254 is an apocalyptic number.

145033340211254 is a deficient number, since it is larger than the sum of its proper divisors (94091877740758).

145033340211254 is a wasteful number, since it uses less digits than its factorization.

145033340211254 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 599311323211 (or 599311323200 counting only the distinct ones).

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 145033340211254 its reverse (452112043330541), we get a palindrome (597145383541795).

The spelling of 145033340211254 in words is "one hundred forty-five trillion, thirty-three billion, three hundred forty million, two hundred eleven thousand, two hundred fifty-four".

Divisors: 1 2 11 22 121 242 599311323187 1198622646374 6592424555057 13184849110114 72516670105627 145033340211254