1450341331 has 2 divisors, whose sum is σ = 1450341332. Its totient is φ = 1450341330.

The previous prime is 1450341313. The next prime is 1450341341. The reversal of 1450341331 is 1331430541.

Together with previous prime (1450341313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1450341331 - 2¹⁷ = 1450210259 is a prime.

It is a super-2 number, since 2×1450341331² = 4206979952813703122, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1450341296 and 1450341305.

It is not a weakly prime, because it can be changed into another prime (1450341311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 725170665 + 725170666.

It is an arithmetic number, because the mean of its divisors is an integer number (725170666).

Almost surely, 2^1450341331 is an apocalyptic number.

1450341331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1450341331 is an equidigital number, since it uses as much as digits as its factorization.

1450341331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

The square root of 1450341331 is about 38083.3471611937. The cubic root of 1450341331 is about 1131.9400018457.

Adding to 1450341331 its reverse (1331430541), we get a palindrome (2781771872).

The spelling of 1450341331 in words is "one billion, four hundred fifty million, three hundred forty-one thousand, three hundred thirty-one".