Base | Representation |
---|---|
bin | 10101000110110000010… |
… | …000100100011011101111 |
3 | 12010122122011022101001110 |
4 | 111012300100210123233 |
5 | 142230314421043203 |
6 | 3030141532043103 |
7 | 206533205021235 |
oct | 25066020443357 |
9 | 5118564271043 |
10 | 1450361112303 |
11 | 50a105045364 |
12 | 1b510b003493 |
13 | a69cb4209cc |
14 | 502aac9a955 |
15 | 27ad9585d03 |
hex | 151b04246ef |
1450361112303 has 4 divisors (see below), whose sum is σ = 1933814816408. Its totient is φ = 966907408200.
The previous prime is 1450361112289. The next prime is 1450361112383. The reversal of 1450361112303 is 3032111630541.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1450361112303 - 213 = 1450361104111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1450361112383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241726852048 + ... + 241726852053.
It is an arithmetic number, because the mean of its divisors is an integer number (483453704102).
Almost surely, 21450361112303 is an apocalyptic number.
1450361112303 is a deficient number, since it is larger than the sum of its proper divisors (483453704105).
1450361112303 is an equidigital number, since it uses as much as digits as its factorization.
1450361112303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 483453704104.
The product of its (nonzero) digits is 6480, while the sum is 30.
Adding to 1450361112303 its reverse (3032111630541), we get a palindrome (4482472742844).
The spelling of 1450361112303 in words is "one trillion, four hundred fifty billion, three hundred sixty-one million, one hundred twelve thousand, three hundred three".
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