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1450444242119 is a prime number
BaseRepresentation
bin10101000110110101001…
…101101011110011000111
312010122211221201210201112
4111012311031223303013
5142231002211221434
63030154101515235
7206535234431225
oct25066515536307
95118757653645
101450444242119
1150a147a63a94
121b5132a12b1b
13a6a12708852
14502b7d39b15
1527ae1a06dce
hex151b536bcc7

1450444242119 has 2 divisors, whose sum is σ = 1450444242120. Its totient is φ = 1450444242118.

The previous prime is 1450444242101. The next prime is 1450444242127. The reversal of 1450444242119 is 9112424440541.

It is a strong prime.

It is an emirp because it is prime and its reverse (9112424440541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1450444242119 - 228 = 1450175806663 is a prime.

It is a super-2 number, since 2×14504442421192 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1450444442119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 725222121059 + 725222121060.

It is an arithmetic number, because the mean of its divisors is an integer number (725222121060).

Almost surely, 21450444242119 is an apocalyptic number.

1450444242119 is a deficient number, since it is larger than the sum of its proper divisors (1).

1450444242119 is an equidigital number, since it uses as much as digits as its factorization.

1450444242119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 184320, while the sum is 41.

The spelling of 1450444242119 in words is "one trillion, four hundred fifty billion, four hundred forty-four million, two hundred forty-two thousand, one hundred nineteen".