Base | Representation |
---|---|
bin | 1000011100010110101… |
… | …1110101001101110001 |
3 | 111212101211011000010101 |
4 | 2013011223311031301 |
5 | 4334030413204411 |
6 | 150345120032401 |
7 | 13323326045434 |
oct | 2070553651561 |
9 | 455354130111 |
10 | 145050522481 |
11 | 56574269467 |
12 | 24141162701 |
13 | 108a802ca37 |
14 | 70402c181b |
15 | 3b8e3078c1 |
hex | 21c5af5371 |
145050522481 has 2 divisors, whose sum is σ = 145050522482. Its totient is φ = 145050522480.
The previous prime is 145050522479. The next prime is 145050522493. The reversal of 145050522481 is 184225050541.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98601652081 + 46448870400 = 314009^2 + 215520^2 .
It is a cyclic number.
It is not a de Polignac number, because 145050522481 - 21 = 145050522479 is a prime.
It is a super-2 number, since 2×1450505224812 (a number of 23 digits) contains 22 as substring.
Together with 145050522479, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 145050522481.
It is not a weakly prime, because it can be changed into another prime (145050502481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72525261240 + 72525261241.
It is an arithmetic number, because the mean of its divisors is an integer number (72525261241).
Almost surely, 2145050522481 is an apocalyptic number.
It is an amenable number.
145050522481 is a deficient number, since it is larger than the sum of its proper divisors (1).
145050522481 is an equidigital number, since it uses as much as digits as its factorization.
145050522481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64000, while the sum is 37.
The spelling of 145050522481 in words is "one hundred forty-five billion, fifty million, five hundred twenty-two thousand, four hundred eighty-one".
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