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1450634126432 = 2545332316451
BaseRepresentation
bin10101000111000000100…
…010000010010001100000
312010200100012000221000212
4111013000202002101200
5142231344314021212
63030225003433252
7206543031424631
oct25070042022140
95120305027025
101450634126432
1150a235167977
121b5186525828
13a6a42b6072a
14502d5247888
1527b03513e22
hex151c0882460

1450634126432 has 12 divisors (see below), whose sum is σ = 2855935936476. Its totient is φ = 725317063200.

The previous prime is 1450634126413. The next prime is 1450634126449. The reversal of 1450634126432 is 2346214360541.

It is a super-3 number, since 3×14506341264323 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 1450634126432.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22666158194 + ... + 22666158257.

It is an arithmetic number, because the mean of its divisors is an integer number (237994661373).

Almost surely, 21450634126432 is an apocalyptic number.

It is an amenable number.

1450634126432 is a deficient number, since it is larger than the sum of its proper divisors (1405301810044).

1450634126432 is an equidigital number, since it uses as much as digits as its factorization.

1450634126432 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45332316461 (or 45332316453 counting only the distinct ones).

The product of its (nonzero) digits is 414720, while the sum is 41.

Adding to 1450634126432 its reverse (2346214360541), we get a palindrome (3796848486973).

The spelling of 1450634126432 in words is "one trillion, four hundred fifty billion, six hundred thirty-four million, one hundred twenty-six thousand, four hundred thirty-two".

Divisors: 1 2 4 8 16 32 45332316451 90664632902 181329265804 362658531608 725317063216 1450634126432