Base | Representation |
---|---|
bin | 1101001100100110100010… |
… | …1101111111010011010111 |
3 | 1220101011020202012212012212 |
4 | 3103021220231333103113 |
5 | 3400213300020141434 |
6 | 50505512425304035 |
7 | 3025216126326044 |
oct | 323115055772327 |
9 | 56334222185185 |
10 | 14510156412119 |
11 | 46947a5019905 |
12 | 17641ba03501b |
13 | 8133c02c4824 |
14 | 38241c4cc1cb |
15 | 1a26984d88ce |
hex | d3268b7f4d7 |
14510156412119 has 2 divisors, whose sum is σ = 14510156412120. Its totient is φ = 14510156412118.
The previous prime is 14510156412091. The next prime is 14510156412133. The reversal of 14510156412119 is 91121465101541.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14510156412119 is a prime.
It is a super-2 number, since 2×145101564121192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14510156412179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7255078206059 + 7255078206060.
It is an arithmetic number, because the mean of its divisors is an integer number (7255078206060).
Almost surely, 214510156412119 is an apocalyptic number.
14510156412119 is a deficient number, since it is larger than the sum of its proper divisors (1).
14510156412119 is an equidigital number, since it uses as much as digits as its factorization.
14510156412119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 41.
The spelling of 14510156412119 in words is "fourteen trillion, five hundred ten billion, one hundred fifty-six million, four hundred twelve thousand, one hundred nineteen".
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