Base | Representation |
---|---|
bin | 1000011100100010111… |
… | …1001001110110111001 |
3 | 111212112101111100221011 |
4 | 2013020233021312321 |
5 | 4334132020200423 |
6 | 150354145313521 |
7 | 13324520212312 |
oct | 2071057116671 |
9 | 455471440834 |
10 | 145101725113 |
11 | 565a0160794 |
12 | 241563358a1 |
13 | 108b5819657 |
14 | 704700d609 |
15 | 3b93a6db0d |
hex | 21c8bc9db9 |
145101725113 has 2 divisors, whose sum is σ = 145101725114. Its totient is φ = 145101725112.
The previous prime is 145101725101. The next prime is 145101725159. The reversal of 145101725113 is 311527101541.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 120998231104 + 24103494009 = 347848^2 + 155253^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-145101725113 is a prime.
It is a super-2 number, since 2×1451017251132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (145101725413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72550862556 + 72550862557.
It is an arithmetic number, because the mean of its divisors is an integer number (72550862557).
Almost surely, 2145101725113 is an apocalyptic number.
It is an amenable number.
145101725113 is a deficient number, since it is larger than the sum of its proper divisors (1).
145101725113 is an equidigital number, since it uses as much as digits as its factorization.
145101725113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4200, while the sum is 31.
Adding to 145101725113 its reverse (311527101541), we get a palindrome (456628826654).
The spelling of 145101725113 in words is "one hundred forty-five billion, one hundred one million, seven hundred twenty-five thousand, one hundred thirteen".
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