Base | Representation |
---|---|
bin | 100000111111100011000110… |
… | …110110100111100000001100 |
3 | 201000202212002212212112122210 |
4 | 200333203012312213200030 |
5 | 123004343014400200122 |
6 | 1232340031532110420 |
7 | 42364312026525210 |
oct | 4077430666474014 |
9 | 630685085775583 |
10 | 145104511334412 |
11 | 42264528866153 |
12 | 14336287305410 |
13 | 62c73b1b28c36 |
14 | 27b914ad10940 |
15 | 11b977c02440c |
hex | 83f8c6da780c |
145104511334412 has 48 divisors (see below), whose sum is σ = 393288730188032. Its totient is φ = 40778785385280.
The previous prime is 145104511334389. The next prime is 145104511334429. The reversal of 145104511334412 is 214433115401541.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14159295358 + ... + 14159305605.
Almost surely, 2145104511334412 is an apocalyptic number.
145104511334412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
145104511334412 is an abundant number, since it is smaller than the sum of its proper divisors (248184218853620).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
145104511334412 is a wasteful number, since it uses less digits than its factorization.
145104511334412 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28318601038 (or 28318601036 counting only the distinct ones).
The product of its (nonzero) digits is 115200, while the sum is 39.
Adding to 145104511334412 its reverse (214433115401541), we get a palindrome (359537626735953).
The spelling of 145104511334412 in words is "one hundred forty-five trillion, one hundred four billion, five hundred eleven million, three hundred thirty-four thousand, four hundred twelve".
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