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1451093479447 is a prime number
BaseRepresentation
bin10101000111011011111…
…010010101000000010111
312010201112012101110220111
4111013123322111000113
5142233314412320242
63030342333143451
7206560310030353
oct25073372250027
95121465343814
101451093479447
1150a450491667
121b529432ab87
13a6ab7083651
145033a25c463
1527b2d9ed817
hex151dbe95017

1451093479447 has 2 divisors, whose sum is σ = 1451093479448. Its totient is φ = 1451093479446.

The previous prime is 1451093479417. The next prime is 1451093479471. The reversal of 1451093479447 is 7449743901541.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1451093479447 is a prime.

It is a super-2 number, since 2×14510934794472 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1451093479391 and 1451093479400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1451093479417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 725546739723 + 725546739724.

It is an arithmetic number, because the mean of its divisors is an integer number (725546739724).

Almost surely, 21451093479447 is an apocalyptic number.

1451093479447 is a deficient number, since it is larger than the sum of its proper divisors (1).

1451093479447 is an equidigital number, since it uses as much as digits as its factorization.

1451093479447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15240960, while the sum is 58.

The spelling of 1451093479447 in words is "one trillion, four hundred fifty-one billion, ninety-three million, four hundred seventy-nine thousand, four hundred forty-seven".