Base | Representation |
---|---|
bin | 1000011100101000010… |
… | …1011000111010010011 |
3 | 111212120222000212120222 |
4 | 2013022011120322103 |
5 | 4334203312044110 |
6 | 150400314023255 |
7 | 13325213314166 |
oct | 2071205307223 |
9 | 455528025528 |
10 | 145124331155 |
11 | 566019a0a71 |
12 | 24161a17b2b |
13 | 108ba402ccb |
14 | 704a015add |
15 | 3b95a36c55 |
hex | 21ca158e93 |
145124331155 has 8 divisors (see below), whose sum is σ = 174202784784. Its totient is φ = 116063740000.
The previous prime is 145124331101. The next prime is 145124331173. The reversal of 145124331155 is 551133421541.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 145124331155 - 222 = 145120136851 is a prime.
It is a super-2 number, since 2×1451243311552 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4447736 + ... + 4480245.
It is an arithmetic number, because the mean of its divisors is an integer number (21775348098).
Almost surely, 2145124331155 is an apocalyptic number.
145124331155 is a deficient number, since it is larger than the sum of its proper divisors (29078453629).
145124331155 is an equidigital number, since it uses as much as digits as its factorization.
145124331155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8931237.
The product of its digits is 36000, while the sum is 35.
Adding to 145124331155 its reverse (551133421541), we get a palindrome (696257752696).
The spelling of 145124331155 in words is "one hundred forty-five billion, one hundred twenty-four million, three hundred thirty-one thousand, one hundred fifty-five".
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