Search a number
-
+
145124331173 is a prime number
BaseRepresentation
bin1000011100101000010…
…1011000111010100101
3111212120222000212121122
42013022011120322211
54334203312044143
6150400314023325
713325213314223
oct2071205307245
9455528025548
10145124331173
11566019a0a88
1224161a17b45
13108ba403013
14704a015b13
153b95a36c68
hex21ca158ea5

145124331173 has 2 divisors, whose sum is σ = 145124331174. Its totient is φ = 145124331172.

The previous prime is 145124331101. The next prime is 145124331197. The reversal of 145124331173 is 371133421541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 136827489604 + 8296841569 = 369902^2 + 91087^2 .

It is a cyclic number.

It is not a de Polignac number, because 145124331173 - 224 = 145107553957 is a prime.

It is a super-2 number, since 2×1451243311732 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145124331773) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72562165586 + 72562165587.

It is an arithmetic number, because the mean of its divisors is an integer number (72562165587).

Almost surely, 2145124331173 is an apocalyptic number.

It is an amenable number.

145124331173 is a deficient number, since it is larger than the sum of its proper divisors (1).

145124331173 is an equidigital number, since it uses as much as digits as its factorization.

145124331173 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 30240, while the sum is 35.

The spelling of 145124331173 in words is "one hundred forty-five billion, one hundred twenty-four million, three hundred thirty-one thousand, one hundred seventy-three".