Base | Representation |
---|---|
bin | 10000000010100100001… |
… | …11001001111111100101 |
3 | 1221200120102202122220222 |
4 | 20001102013021333211 |
5 | 33012210123442131 |
6 | 1101104233534125 |
7 | 54550412534153 |
oct | 10012207117745 |
9 | 1850512678828 |
10 | 551133421541 |
11 | 1a28094a296a |
12 | 8a991574345 |
13 | 3cc82970921 |
14 | 1c9642b23d3 |
15 | e509c6187b |
hex | 80521c9fe5 |
551133421541 has 2 divisors, whose sum is σ = 551133421542. Its totient is φ = 551133421540.
The previous prime is 551133421513. The next prime is 551133421577. The reversal of 551133421541 is 145124331155.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 434121536641 + 117011884900 = 658879^2 + 342070^2 .
It is a cyclic number.
It is not a de Polignac number, because 551133421541 - 218 = 551133159397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (551133421841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275566710770 + 275566710771.
It is an arithmetic number, because the mean of its divisors is an integer number (275566710771).
Almost surely, 2551133421541 is an apocalyptic number.
It is an amenable number.
551133421541 is a deficient number, since it is larger than the sum of its proper divisors (1).
551133421541 is an equidigital number, since it uses as much as digits as its factorization.
551133421541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 36000, while the sum is 35.
Adding to 551133421541 its reverse (145124331155), we get a palindrome (696257752696).
The spelling of 551133421541 in words is "five hundred fifty-one billion, one hundred thirty-three million, four hundred twenty-one thousand, five hundred forty-one".
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