Base | Representation |
---|---|
bin | 100000111111110110100100… |
… | …101010010101000111011111 |
3 | 201000211212001112011000022121 |
4 | 200333312210222111013133 |
5 | 123010213321101241021 |
6 | 1232353405533123411 |
7 | 42365652003645406 |
oct | 4077664452250737 |
9 | 630755045130277 |
10 | 145125412524511 |
11 | 42272383a5a681 |
12 | 1433a33b029567 |
13 | 62c9363125b43 |
14 | 27ba170b8263d |
15 | 11ba0a1e54741 |
hex | 83fda4a951df |
145125412524511 has 2 divisors, whose sum is σ = 145125412524512. Its totient is φ = 145125412524510.
The previous prime is 145125412524497. The next prime is 145125412524593. The reversal of 145125412524511 is 115425214521541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 145125412524511 - 25 = 145125412524479 is a prime.
It is a super-2 number, since 2×1451254125245112 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145125412521511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72562706262255 + 72562706262256.
It is an arithmetic number, because the mean of its divisors is an integer number (72562706262256).
Almost surely, 2145125412524511 is an apocalyptic number.
145125412524511 is a deficient number, since it is larger than the sum of its proper divisors (1).
145125412524511 is an equidigital number, since it uses as much as digits as its factorization.
145125412524511 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 320000, while the sum is 43.
The spelling of 145125412524511 in words is "one hundred forty-five trillion, one hundred twenty-five billion, four hundred twelve million, five hundred twenty-four thousand, five hundred eleven".
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