145130014203133 has 2 divisors, whose sum is σ = 145130014203134. Its totient is φ = 145130014203132.

The previous prime is 145130014203023. The next prime is 145130014203199. The reversal of 145130014203133 is 331302410031541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107338344018084 + 37791670185049 = 10360422^2 + 6147493^2 .

It is a cyclic number.

It is not a de Polignac number, because 145130014203133 - 2³⁷ = 144992575249661 is a prime.

It is a super-3 number, since 3×145130014203133³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 145130014203095 and 145130014203104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145130014203233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72565007101566 + 72565007101567.

It is an arithmetic number, because the mean of its divisors is an integer number (72565007101567).

Almost surely, 2^{145130014203133} is an apocalyptic number.

It is an amenable number.

145130014203133 is a deficient number, since it is larger than the sum of its proper divisors (1).

145130014203133 is an equidigital number, since it uses as much as digits as its factorization.

145130014203133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 145130014203133 its reverse (331302410031541), we get a palindrome (476432424234674).

The spelling of 145130014203133 in words is "one hundred forty-five trillion, one hundred thirty billion, fourteen million, two hundred three thousand, one hundred thirty-three".