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14519985463 is a prime number
BaseRepresentation
bin11011000010111010…
…10110010100110111
31101110220220200112101
431201131112110313
5214214104013323
610400445402531
71022550561064
oct154135262467
941426820471
1014519985463
116181175a95
122992869447
1314a5270899
149ba591c6b
1559eae7dad
hex361756537

14519985463 has 2 divisors, whose sum is σ = 14519985464. Its totient is φ = 14519985462.

The previous prime is 14519985457. The next prime is 14519985521. The reversal of 14519985463 is 36458991541.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14519985463 - 233 = 5930050871 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14519985433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7259992731 + 7259992732.

It is an arithmetic number, because the mean of its divisors is an integer number (7259992732).

Almost surely, 214519985463 is an apocalyptic number.

14519985463 is a deficient number, since it is larger than the sum of its proper divisors (1).

14519985463 is an equidigital number, since it uses as much as digits as its factorization.

14519985463 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4665600, while the sum is 55.

The spelling of 14519985463 in words is "fourteen billion, five hundred nineteen million, nine hundred eighty-five thousand, four hundred sixty-three".