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14520035070341 is a prime number
BaseRepresentation
bin1101001101001011010110…
…0010000101000110000101
31220102002202012122200201022
43103102311202011012011
53400344012434222331
650514224555240525
73026016001460633
oct323226542050605
956362665580638
1014520035070341
114698a04295a59
1217660b6449145
13814305b08418
14382ab84a6353
151a2a758c867b
hexd34b5885185

14520035070341 has 2 divisors, whose sum is σ = 14520035070342. Its totient is φ = 14520035070340.

The previous prime is 14520035070313. The next prime is 14520035070379. The reversal of 14520035070341 is 14307053002541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14513547412225 + 6487658116 = 3809665^2 + 80546^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14520035070341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14520035072341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7260017535170 + 7260017535171.

It is an arithmetic number, because the mean of its divisors is an integer number (7260017535171).

Almost surely, 214520035070341 is an apocalyptic number.

It is an amenable number.

14520035070341 is a deficient number, since it is larger than the sum of its proper divisors (1).

14520035070341 is an equidigital number, since it uses as much as digits as its factorization.

14520035070341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 35.

Adding to 14520035070341 its reverse (14307053002541), we get a palindrome (28827088072882).

The spelling of 14520035070341 in words is "fourteen trillion, five hundred twenty billion, thirty-five million, seventy thousand, three hundred forty-one".