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145200432529987 is a prime number
BaseRepresentation
bin100001000000111100011100…
…001100111100001001000011
3201001010000200210112011002221
4201000330130030330021003
5123012430441211424422
61232452054032151511
742404246035323502
oct4100743414741103
9631100623464087
10145200432529987
11422a11808830aa
1214350997098597
13630345a5b4b23
1427bda4a386839
1511bbee311e3c7
hex840f1c33c243

145200432529987 has 2 divisors, whose sum is σ = 145200432529988. Its totient is φ = 145200432529986.

The previous prime is 145200432529949. The next prime is 145200432530113. The reversal of 145200432529987 is 789925234002541.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 145200432529987 - 223 = 145200424141379 is a prime.

It is a super-3 number, since 3×1452004325299873 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (145200432529387) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72600216264993 + 72600216264994.

It is an arithmetic number, because the mean of its divisors is an integer number (72600216264994).

Almost surely, 2145200432529987 is an apocalyptic number.

145200432529987 is a deficient number, since it is larger than the sum of its proper divisors (1).

145200432529987 is an equidigital number, since it uses as much as digits as its factorization.

145200432529987 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43545600, while the sum is 61.

The spelling of 145200432529987 in words is "one hundred forty-five trillion, two hundred billion, four hundred thirty-two million, five hundred twenty-nine thousand, nine hundred eighty-seven".