1452114011281 has 2 divisors, whose sum is σ = 1452114011282. Its totient is φ = 1452114011280.

The previous prime is 1452114011213. The next prime is 1452114011287. The reversal of 1452114011281 is 1821104112541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 760530503056 + 691583508225 = 872084^2 + 831615^2 .

It is a cyclic number.

It is not a de Polignac number, because 1452114011281 - 2¹¹ = 1452114009233 is a prime.

It is a super-2 number, since 2×1452114011281² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1452114011287) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726057005640 + 726057005641.

It is an arithmetic number, because the mean of its divisors is an integer number (726057005641).

Almost surely, 2^{1452114011281} is an apocalyptic number.

It is an amenable number.

1452114011281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1452114011281 is an equidigital number, since it uses as much as digits as its factorization.

1452114011281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2560, while the sum is 31.

The spelling of 1452114011281 in words is "one trillion, four hundred fifty-two billion, one hundred fourteen million, eleven thousand, two hundred eighty-one".