1452114011213 has 2 divisors, whose sum is σ = 1452114011214. Its totient is φ = 1452114011212.

The previous prime is 1452114011197. The next prime is 1452114011281. The reversal of 1452114011213 is 3121104112541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1228402038889 + 223711972324 = 1108333^2 + 472982^2 .

It is an emirp because it is prime and its reverse (3121104112541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1452114011213 - 2⁴ = 1452114011197 is a prime.

It is a super-2 number, since 2×1452114011213² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1452164011213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726057005606 + 726057005607.

It is an arithmetic number, because the mean of its divisors is an integer number (726057005607).

Almost surely, 2^{1452114011213} is an apocalyptic number.

It is an amenable number.

1452114011213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1452114011213 is an equidigital number, since it uses as much as digits as its factorization.

1452114011213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 26.

Adding to 1452114011213 its reverse (3121104112541), we get a palindrome (4573218123754).

The spelling of 1452114011213 in words is "one trillion, four hundred fifty-two billion, one hundred fourteen million, eleven thousand, two hundred thirteen".