Base | Representation |
---|---|
bin | 1000011100111101010… |
… | …0101000010100111101 |
3 | 111212211002101201012010 |
4 | 2013033110220110331 |
5 | 4334343311300131 |
6 | 150413133401433 |
7 | 13330331304144 |
oct | 2071724502475 |
9 | 455732351163 |
10 | 145212212541 |
11 | 56647565610 |
12 | 24187339279 |
13 | 10902692826 |
14 | 705797075b |
15 | 3b9d5e5b46 |
hex | 21cf52853d |
145212212541 has 32 divisors (see below), whose sum is σ = 217826902656. Its totient is φ = 85273344000.
The previous prime is 145212212533. The next prime is 145212212549.
145212212541 is nontrivially palindromic in base 10.
145212212541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (145212212533) and next prime (145212212549).
It is not a de Polignac number, because 145212212541 - 23 = 145212212533 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 145212212499 and 145212212508.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (145212212549) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 47521 + ... + 541001.
It is an arithmetic number, because the mean of its divisors is an integer number (6807090708).
Almost surely, 2145212212541 is an apocalyptic number.
145212212541 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
145212212541 is a deficient number, since it is larger than the sum of its proper divisors (72614690115).
145212212541 is a wasteful number, since it uses less digits than its factorization.
145212212541 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 493773.
The product of its digits is 6400, while the sum is 30.
It can be divided in two parts, 145212 and 212541, that added together give a palindrome (357753).
The spelling of 145212212541 in words is "one hundred forty-five billion, two hundred twelve million, two hundred twelve thousand, five hundred forty-one".
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