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1452164011213 is a prime number
BaseRepresentation
bin10101001000011011101…
…110000101010011001101
312010211021210210010102011
4111020123232011103031
5142243012441324323
63031040454301221
7206625656301256
oct25103356052315
95124253703364
101452164011213
1150a94a7a9a63
121b5532957811
13a6c27ab73b6
14503dc4c9b2d
1527b929b320d
hex1521bb854cd

1452164011213 has 2 divisors, whose sum is σ = 1452164011214. Its totient is φ = 1452164011212.

The previous prime is 1452164011189. The next prime is 1452164011231. The reversal of 1452164011213 is 3121104612541.

Together with next prime (1452164011231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 931568571684 + 520595439529 = 965178^2 + 721523^2 .

It is a cyclic number.

It is not a de Polignac number, because 1452164011213 - 29 = 1452164010701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1452164011273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726082005606 + 726082005607.

It is an arithmetic number, because the mean of its divisors is an integer number (726082005607).

Almost surely, 21452164011213 is an apocalyptic number.

It is an amenable number.

1452164011213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1452164011213 is an equidigital number, since it uses as much as digits as its factorization.

1452164011213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 1452164011213 its reverse (3121104612541), we get a palindrome (4573268623754).

The spelling of 1452164011213 in words is "one trillion, four hundred fifty-two billion, one hundred sixty-four million, eleven thousand, two hundred thirteen".